3x^(1/2)+x^(1/4)-4=0

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Solution for 3x^(1/2)+x^(1/4)-4=0 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

3*x^(1/2)+x^(1/4)-4 = 0

t_1 = x^(1/4)

3*t_1^2+1*t_1^1-4 = 0

3*t_1^2+t_1-4 = 0

DELTA = 1^2-(-4*3*4)

DELTA = 49

DELTA > 0

t_1 = (49^(1/2)-1)/(2*3) or t_1 = (-49^(1/2)-1)/(2*3)

t_1 = 1 or t_1 = -4/3

t_1 = -4/3

x^(1/4)+4/3 = 0

1*x^(1/4) = -4/3 // : 1

x^(1/4) = -4/3

( -4/3 < 0 i 1/4 in (0:1) ) => x naleu017Cy do O

t_1 = 1

x^(1/4)-1 = 0

1*x^(1/4) = 1 // : 1

x^(1/4) = 1

x^(1/4) = 1 // ^ 4

x = 1

x = 1

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